1、错误提示

FatalErrorException in Handler.php line 38:

Uncaught TypeError: Argument 1 passed to App\Exceptions\Handler::report() must be an instance of Exception, instance of Error given, called in D:\www\activity\vendor\compiled.php on line 1817 and defined in D:\www\activity\app\Exceptions\Handler.php:38

Stack trace:

#0 D:\www\activity\vendor\compiled.php(1817): App\Exceptions\Handler->report(Object(Error))

#1 [internal function]: Illuminate\Foundation\Bootstrap\HandleExceptions->handleException(Object(Error))

#2 {main}

thrown

原因：D:wwwactivityvendorcompiled.php on line 1817 的变量$e不是Exception的实例对象(对错误提示的翻译……^.^笑cry)

2、解决方案

在提示的错误地方加上变量$e的实例判断，如果不是Exception类型，就new一个

if (!$e instanceof \Exception) {

$e = new FatalThrowableError($e);

}

new完之后的样子：

public function handleException($e)

{

if (!$e instanceof \Exception) {

$e = new FatalThrowableError($e);

}

$this->getExceptionHandler()->report($e);

if ($this->app->runningInConsole()) {

$this->renderForConsole($e);

} else {

$this->renderHttpResponse($e);

}

}